Find the sum of square of 12 consecutive cubical numbers natural starting from 4.
Answers
Answered by
1
Answer:
Given: sum of the squares of two consecutive natural numbers is 313
To find the numbers
Sol: Let 1 number be x. Since the numbers are consecutive, the other number would be x+1.
Square both and add together to equal 313.
x
2
+(x+1)
2
=313
x
2
+x
2
+2x+1=313
2x
2
+2x−312=0
x
2
+x−156=0
(x−12)(x+13)=0
x=12,x=−13
given numbers are natural . so x=12 and x+1=13 are the two numbers.
Similar questions