Question

Find the sum of squares of first 15 natural numbet

Answer 1

1^2=1

2^2=4

3^2=9

4^2=16

5^2=25

6^2=36

7^2=49

8^2=64

9^2=81

10^2=100

11^2=121

12^2=144

13^2=169

14^2=196

15^2=225

16^2=256

17^2=289

18^2=324

19^2=361

20^2=400

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Answer 2

Answer:

the sum of the squares of first n natural numbers = n(n+1)(2n+1)6

Step-by-step explanation:

So, 15(15+1)(2*15+1)6

15*16*31*6

=44640

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