Question

find the sum of successor of 'n' and the predessor of 'n' is ? a) n b) n2 c) 2n d) 2+n in explanation..​

Answer 1

Successor of n = n+1

Predecessor of n = n-1

Sum = (n+1)+(n-1)

= n+1+n-1

= 2n

ANSWER → c) 2n

Answer 2

Answer:

Successor of n :- n + 1

predecessor of n = n-1

Sum of (n+1) + (n-1),

= 2n .

Correct option is C (2n)

HOPE IT HELPS YOU!!

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