Question

find the sum of ten consecutive natural number.explnation​

Answer 1

Answer:

sum of first 10 natural numbers is

Sn = n/2{a+(n-1)d}

here n= 10, a=1, d=1

putting the value , 10/2{1+(10-1)×1 }

5 ×10 = 50

hope it helps you

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Answer 2

Step-by-step explanation:

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