find the sum of terms of an A.P. 3,6,9,.....,300.
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Here is your answer
ap=3,6,9,.....,300
an = 300
a+(n-1)×d = 300
3+(n-1)×3 = 300
3+3n-3 = 300
3n = 300
n=300/3 = 100
sn = n/2 × [ First term + Last term ]
s100 = 100/2 × ( 3+300)
s100 = 50×303 = 15150
Hope it helps you ^_^
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ap=3,6,9,.....,300
an = 300
a+(n-1)×d = 300
3+(n-1)×3 = 300
3+3n-3 = 300
3n = 300
n=300/3 = 100
sn = n/2 × [ First term + Last term ]
s100 = 100/2 × ( 3+300)
s100 = 50×303 = 15150
Hope it helps you ^_^
Mark as brainliest
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1 . HOPE ITS YOUR HELP THANK YOU0
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