find the sum of that 35 term of the sequence 1,3,5...
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Answer:
Sum of 35 term=1225
Step-by-step explanation:
FORMULA : Sn=n/2[2a+(n-1)d]
a=1
d=2
n=35
S35=35/2[2(1)+(35-1)2]
=35/2[ 2+34(2)]
=35/2[ 2+68]
=35/2×70
=35×35
=1,225
hope it's helpful!!!
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