Find the sum of the 10 terms of AP 30,35,40....
Answers
Answered by
0
Answer:S10= 75 ; subscribe to my youtube channel #smtuitions
Step-by-step explanation:
AP: 30 , 35 , 40 .....
a1=30 , a2=35 , a3=40
d=a2-a1
d=35-30
d=-5
Sn=n/2[2a+ (n-1)d ]
S10=10/2[2*30 + (10-1)*(-5)]
S10=5[60+9*(-5) ]
S10=5[60+(-45) ]
S10=5[60-45]
S10=5*15
S10=75
Answered by
0
Answer:
S10=525
Step-by-step explanation:
a1 = 30
a2 = 35
d = a2-a1 = 35-30 = 5
an= a+(n-1)d
a10 = a+(10-1)5
a10 = 30+45
a10 =75
Now,
Sn= n/2(a+l)
S10=10/2(30+75)
S10=5×105
S10=525
Remember:
an= l (last term)
a10=last term
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