find the sum of the 11th term of the AP :2,5,8.................
Answers
Answered by
1
Answer:
32
Step-by-step explanation:
tn= a+ (n-1)*d
where a= first no.(2)
n= term we required(11)
d= difference (3)
therefore
t11 = 2+(11-1)*3
= 2+10*3
= 2+30
= 32
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