Find the sum of the 11th terms of an AP .whose middle term is 30.
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12
n(number of terms)=11
middle term=11
sum(sn)= n*middle term
=11*30
=330
sum of the 11 terms=330
middle term=11
sum(sn)= n*middle term
=11*30
=330
sum of the 11 terms=330
Answered by
14
Number of term= 11
Middle term= 30
Sum=Number of term*Middle term
Sum=11*30
=330.
Middle term= 30
Sum=Number of term*Middle term
Sum=11*30
=330.
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