Find the sum of the 20th term of the Ap 2,5,8,,,,20
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first term =2 and difference=3
n=20
Sn= n/2[2a+(n-1)d]
Sn = 20/2[2×2+(20-1)3]
=10[4+19×3]
=10(4+57)
=10×61
=610
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