Question

Find the sum of the A.P.: 2, 7/2 , 5. ...... upto 32 terms.

Answer 1

Answer:

Sum of the Given A.P is 808

also, common difference (d) = 3/2

Step-by-step explanation:

$sum = \frac{n}{2} (2a + (n - 1)d)$

$sum = 16(4 + 31 \times \frac{3}{2} )$

$sum = 16(4 + \frac{93}{3} )$

$sum = 808$

Therefore, Sum of 32 terms is 808.

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Answer 2

Given:-

→First Term(a)=2

→Common Difference(d)=(a²-a¹)=$\frac{7}{2}$-2=$\frac{3}{2}$

$\rule{200}{1}$

To Find:-

→The Sum of 32 terms?

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Answer:-

♦Using Formula♦

→Sⁿ=$\frac{n}{2}$×[2a+(n-1)d]

♦Putting the Values♦

→S³²=$\frac{\cancel{32}}{\cancel{2}}$×[2×2+(32-1)×$\frac{3}{2}$ ]

→S³²=16×[4+31×$\frac{3}{2}$ ]

→S³²=16×[4+$\frac{93}{2}$ ]

→S³²=16×[4+46.5]

→S³²=16×[50.5]

→S³²=808

๛Hence,Sum of 32 Terms is 808.

$\rule{200}{2}$