find the sum of the all natural no of from 1to1000
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Answer:
500500
Step-by-step explanation:
The sequence of integers starting from 1 to 1000 is given by
1,2,3,4,...,1000
The above sequence has 1000 terms. The first term is 1 and the last term is 1000 and the common difference is equal to 1.
We have the formula that gives the sum of the first n terms of an arithmetic sequence knowing the first and last term of the sequence and the number of terms (see formula above).
s 1000 =[1000(1+1000)]/2
=500500
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Answer:
Answer=10 I hope you my answer is correct
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