Find the sum of the all numbers between 800 and 1100 which are divisible by 79.
Answers
Answered by
1
Answer:
869 ,948,1027 are the numbers which is divisible by 79
Explanation:
And other no are 79 *11,79*12, 79*13
Answered by
1
first term, a = 869 --------(choose first number divisible by 79 b/w 800 and 1100)
last term,l = 1027---------(choose last number divisible by 79 b/w 800 and 1100)
so the A.P is
869,948...........1027 with common difference, d = 79
now,
l= a+(n-1)d
1027 = 869 +(n-1)79
=>> n-1 = (1027-869)/79
=>> n = 2+1 = 3
so number of terms is 3.
=>> sum of all terms, S = n/2(a+l)
= 3/2(869+1027)
= 2844----------------------ANSWE
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