Find the sum of the all numbers from 1 to 100 but not divisible by 3 and 7.. Plz guys solve it.. Quick
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Sum of numbers divisible by 3=16833=1683
Sum of numbers divisible by 7=7357=735
Sum of numbers divisible by 21=21021=210
We need the sum of divisor of 2121 since if we subtract only by the Sum of divisor of 33 and Sum of divisor of 77 then the numbers those are divisible by both 33 & 77 means divisible by 2121 will be subtracted twice but we need to subtract it only once.
∴∴
The sum of numbers not divisible by 33 & 7=7= Sum of first 100100 natural numbers −− Sum of divisor of 3−3− Sum of divisor of 7+7+ Sum of divisor of 2121
=5050−1683−735+210=5050−1683−735+210
=2842
Sum of numbers divisible by 7=7357=735
Sum of numbers divisible by 21=21021=210
We need the sum of divisor of 2121 since if we subtract only by the Sum of divisor of 33 and Sum of divisor of 77 then the numbers those are divisible by both 33 & 77 means divisible by 2121 will be subtracted twice but we need to subtract it only once.
∴∴
The sum of numbers not divisible by 33 & 7=7= Sum of first 100100 natural numbers −− Sum of divisor of 3−3− Sum of divisor of 7+7+ Sum of divisor of 2121
=5050−1683−735+210=5050−1683−735+210
=2842
priyansubehera:
Not understanding clearly plz expalin briefly
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