Question

find the sum of the all3 digits number which leaves the same remainder 2 when divided 5

Answer 1

Step-by-step explanation:

The three digit numbers which leave the same remainder 2 when divided by 5 are

102, 107, ..... 997

This is an AP.

First term, a = 102

Common difference, d = 5

Last term, an = 997

We know that the nth term of an AP is given by:

an = a + (n - 1)d

Sn = [a + l] =  [102 + 997] = 90 1099 = 98910

Hence, the required sum of all three digit numbers which leave the same remainder 2 when divided by 5 is 98910.