Math, asked by tejasmahadev5373, 2 months ago

find the sum of the Ap:2+4+6+___________+56​

Answers

Answered by xSoyaibImtiazAhmedx
0

Here,

  • a ( first term of the AP) = 2
  • d ( common difference) = 2
  • l ( the last term ) = 56

Let the number of terms be n .

So,

l = a + ( n-1 ) d

56 = 2 + ( n-1) 2

54 = (n-1)2

n-1 = 54/2

n - 1 = 27

n = 27 + 1

n = 28

Now,

the sum of the Ap: 2+4+6+_____+56

= S_{28 }

 =  \frac{28}{2} (2 + 56)

 = 14 \times 58

 =   \bold{\boxed{812}}

_________________________

Formula required—

 \bold{\boxed{ \tt{{S_n=  \frac{n}{2} (a + l)}}}}

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