Question

find the sum of the AP in which first term = 2 common difference =3 last term= 59​

Answer 1

Given------Tn=59

a=2, d=3

So, Tn=a+(n-1) ×d

=59=2+(n-1) ×3

=57=(n-1) ×3

=19=(n-1)

=n=20 So,there are 20 terms in the AP

Hence, sum of 20 terms= 20/2(a+l)

=10(2+59)

=610

Hence, the sum of the AP in which first term = 2 common difference =3 last term= 59 is 610

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