Question

find the sum of the area of two squares A1 = 3x + 2 ÷ 7 m² ans A2 = x - 1 ÷7 m², Given that x = 12

Answer 1

Step-by-step explanation:

Given that x=12 and we have to find the area of the two sqaures, A1=3x+2/7 m^2 and A2= x-1/7 m^2

we can put the value A1= 12×2+2÷7 = 36+2/7

36+2/7=254/7 m^2 (354÷7)

Similarly A2= 12-1÷7=83/7 m^2

Adding these two A1+A2=254/7 m^2+83/7 m^2 =337/7 m^2

= 48.14 m^2 (final answer)

Therefore,A1+A2=48.14 m^2