Find the sum of the areas of the two end surface of a right circular cylinder of which the height is 20 m and the curved surface area is 8800 sq m.
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Height of cylinder = 20 m
CSA of cylinder = 8800 m^2
=> 2*pi *r*h = 8800
=> 2*22*20*r/7 = 8800
=> 880r = 8800 * 7
=> r = 10 *7
=> r = 70 m
Sum of Area of two ends = 2 * pi*r^2
= 2* 22*70 *70/7
= 44*70*10
= 30800 m^2
CSA of cylinder = 8800 m^2
=> 2*pi *r*h = 8800
=> 2*22*20*r/7 = 8800
=> 880r = 8800 * 7
=> r = 10 *7
=> r = 70 m
Sum of Area of two ends = 2 * pi*r^2
= 2* 22*70 *70/7
= 44*70*10
= 30800 m^2
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