Find the sum of the arithmetic progressions 50, 46, 42
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Step-by-step explanation:
n=10
first term, a=a1=50
common difference, d=a2 - a1 = 46-50 = -4
By using the formula,
S=n/2(2a+(n-1)d)
Substitute the value of 'a' and 'd',
S= 10/2(100+(a)(-4))
=5(100-36)
=5(64)
=320
So, the total AP is 320. :)
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