Question

Find the sum of the arithmetic series
17+27+37+......417

Answer 1

Answer:

$last \: term = 17 + (n - 1)10 \\ \\ = > 417 = 17 + 10n - 10 \\ \\ = > 410 = 10n \\ \\ = > n = 41 \\ \\ sum = \frac{41}{2} (17 + 417) \\ \\ = \frac{41}{2} \times 434 \\ \\ = 41 \times 217 \\ \\ = 8897$