Find the sum of the certain number of terms of the ap 25 22 19 is 116 find the last term
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1
Answer:
Last term in A.P = 4
Step-by-step explanation:
Given A.P :
25,22,19,...
First term (a) = 25
Common difference (d) = a2-a1
= 22-25
= -3
\* given
Splitting the middle term, we get
n should not be fraction.
Therefore,
n = 8
Now,
Last term (l) = a+(n-1)d
= 25+(8-1)(-3)
= 25+7(-3)
= 25 -21
= 4
Therefore,
Last term in A.P = 4
Thanks!
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