Question

Find the sum of the consecutive cube upto 32 cube

Answer 1

Step-by-step explanation:

:

sum of consecutive cubes upto 'n'=

({ \frac{n(n + 1)}{2} })^{2}(

2

n(n+1)

)

2

so,sum upto 45³

={(45)(46)/2}²

={(45)(23)}²

=(1035)²

=10,71,225.

hope it'll help

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Answer 2

Answer:

957

Step-by-step explanation:

33 ( 33 + 1 / 2 ) ²

33 ( 34 / 2 ) ²

33 ( 17 ) ²

33 × 29 = 957

Sum of first 32 Cubes is 957

Formula for Sum of n Cubes :

n ( n + 1 / 2 ) ²

This is my Navodaya vidyalaya Formula

Hope this helps you to gain Knowledge in Cubes .

Thankyou