Question

Find the sum of the cubes of first 10 natural numbers

Answer 1

(1+2+3+4+5+6+7+8+9+10)^3
55^3
166375

Answer 2

It seems that the sum is always square, but what is even more remarkable is that the sum of the first n cubes, 13+23+... + n 3 = ( n ( n+1)/2)2, which is the square of the n thtriangle number. For example, 13+23+... +103=(10×11/2)2=552 = 3025.