Question

find the sum of the cubes of first 15 natural numbers​

Answer 1

Answer:

$14 \times 45 = 675$

14 cube in 3 times

Answer 2

1*3=1

2*3=8

3*3=27

4*3=64

5*3=125

6*3=216

7*3=343

8*3=512

9*3=729

10*3=1000

11*3=1331

12*3=1728

13*3=2197

14*3= 2744

15*3=3375

Now ,7Te sum of all these cubes...

1+8+27+64+125+216+343+512+729+1000+1331+1728+2197+3375

=11,440....

Here is your answer.... hope it helps you..