Question

Find the Sum of the
divisible by 6.
first 40
positive integers​

Answer 1

$\huge\colorbox{cyan}{Answer ☄}$

The first 40 positive integers that are divisible by 6 are 6,12,18,24.

a=6 and d=6.

We need to find S 40S n = 2n [2a+(n−1)d]

S 40 = 240 [2(6)+(40−1)6]

=20[12+(39)6]

=20(12+234)

=20×246

=4920

Hope it helps ☺️☘️

Answer 2

Answer is attached please mark as brainliest and give thnx