Math, asked by pubgblasters3, 6 months ago

find the sum of the exponents of prime factors in prime factorisation of 196​

Answers

Answered by joelpaulabraham
0

Answer:

The sum of the exponents of prime factors in prime factorisation of 196 is 4

Step-by-step explanation:

We know that,

196 = 2 × 2 × 7 × 7

= 2² × 7²

Now, we must know that,

In a^(m), a is the base and m is the exponent

Here,

the exponent of 2 is 2 and the exponent of 7 is also 2

Thus,

Their sum = 2 + 2 = 4

Thus,

the sum of the exponents of prime factors in prime factorisation of 196 is 4

Hope it helped and you understood it........All the best

Answered by kodeboyinavenkat
0

Answer:

4

Step-by-step explanation:

Answer:

The sum of the exponents of prime factors in prime factorisation of 196 is 4

Step-by-step explanation:

We know that,

196 = 2 × 2 × 7 × 7

= 2² × 7²

Now, we must know that,

In a^(m), a is the base and m is the exponent

Here,

the exponent of 2 is 2 and the exponent of 7 is also 2

Thus,

Their sum = 2 + 2 = 4

Thus,

the sum of the exponents of prime factors in prime factorisation of 196 is 4

it helped and you understood it.All the best

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