Question

Find the sum of the first 10 multiple of 3 using AP.​

Answer 1

Answer:

3+6+9+12+15+18+21+24+27+30

=165

Answer 2

Answer:

first multiple of 3, a=3

no. of terms, n=10

tenth multiple of 3, a10=30

common difference, d=3

now S10=n/2(2a+(n-1)d)

S10=10/2(2*3+(10-1)3)

=5(6+9*3)

=5(6+27)

=5*33

=165

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