find the sum of the first 10 terms of AP 2,7 ,12............
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Answer:
a = 2
d = 7-2 = 5
Sn = n/2[2a+(n-1)d]
S10 = 10 /2 [ 2×2 + (10-1) 5]
= 5 (4 +9×5)
=5 (4+45)
=5 ×49
S10 = 245
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