Question

Find the sum of the first 10 terms of the AP. 2. 7. 12. 17...​

Answer 1

Answer:

Step-by-step explanation:

Sn = n/2(2a+(n-1)d)

a = 2

d = a2-a1= 7 - 2 = 5

n = 10

substitute all these

= 10/2 ((2 x 2)+(10-1)5)

= 5 (4 + (9x5))

= 5 (4 + 45)

= 5 x 49

= 245

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Answer 2

Answer:

a = 2

d = 5

n = 10

Sn = n/2[2a +(n-1)d]

S10 = 10/2[2*2 +(10-1)5]

= 5[4+45]

S10= 245

Hope it helps u.....