find the sum of the first 100positive integers which are divisible by 3
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Answered by
1
Answer:
15150
Step-by-step explanation:
Answered by
7
Answer:
The first 100 positive integers divisible by 3 are 3, 6, 9, 12…. which is an A.P. where a = 3, d = 3, n = 100 & l = 300.
S(100) = (100/2) × (3+300)
= 50 × 303 = 15,150.
Thus, the sum of the first 100 positive integers divisible by 3 is 15150.
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