Question

Find the sum of the first 12 multiples of 8.​

Answer 1

sum of the first 12 multiples of 8 are : 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96

#lovelove!

Answer 2

mate here is your answer

a=8

an=96

n=12

now by using formula we get,

Sn=n/2(a+an)

S12=12/2(8+96)

S12=6(104)

S12=624....

hope it will helpful for you...

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