Find the sum of the first 12 terms of the arithmetic sequence 50, 47, 44, 41, 38, ...
Answers
Hlw
here is ur ans.
Question :-
Find the sum of the first 12 terms of the arithmetic sequence 50, 47, 44, 41, 38, ...
Answer :-
The pattern of arithmetic sequence 50,47,44,41,38, is subtracting 3 now we have given 5 of the numbers of the arithmetic sequence given that we need to the FIRST 12 terms we will do this equation:
12-5=7
Now let's do the finding of the last 7 terms of the arithmetic sequence:
38-3=35
38-3=3535-3=32
38-3=3535-3=3232-3=29
38-3=3535-3=3232-3=2929-3=26
38-3=3535-3=3232-3=2929-3=2626-3=23
38-3=3535-3=3232-3=2929-3=2626-3=2323-3=20
38-3=3535-3=3232-3=2929-3=2626-3=2323-3=2020-3=17
After the finding of the last 7 terms of the arithmetic sequence we finally find the first 12 terms of the arithmetic sequence here it is:
50,47,44,41,38,35,32,29,26,23,20,17
now let's add the first 12 terms of the arithmetic sequence :
50 + 47 + 44+ 41 + 38 + 35 + 32 + 29 + 26 + 23 + 20+ 17= 402
Now 402 is our final answer.
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