Math, asked by anastasiapeters79, 5 months ago

Find the sum of the first 12 terms of the arithmetic sequence 50, 47, 44, 41, 38, ...

Answers

Answered by Anonymous
5

Hlw

here is ur ans.

Question :-

Find the sum of the first 12 terms of the arithmetic sequence 50, 47, 44, 41, 38, ...

Answer :-

The pattern of arithmetic sequence 50,47,44,41,38, is subtracting 3 now we have given 5 of the numbers of the arithmetic sequence given that we need to the FIRST 12 terms we will do this equation:

12-5=7

Now let's do the finding of the last 7 terms of the arithmetic sequence:

38-3=35

38-3=3535-3=32

38-3=3535-3=3232-3=29

38-3=3535-3=3232-3=2929-3=26

38-3=3535-3=3232-3=2929-3=2626-3=23

38-3=3535-3=3232-3=2929-3=2626-3=2323-3=20

38-3=3535-3=3232-3=2929-3=2626-3=2323-3=2020-3=17

After the finding of the last 7 terms of the arithmetic sequence we finally find the first 12 terms of the arithmetic sequence here it is:

50,47,44,41,38,35,32,29,26,23,20,17

now let's add the first 12 terms of the arithmetic sequence :

50 + 47 + 44+ 41 + 38 + 35 + 32 + 29 + 26 + 23 + 20+ 17= 402

Now 402 is our final answer.

PLS MARK AS BRAINLIST

#Miya

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