Question

Find the sum of the first 13 terms of an ap:-6, 0,6,12

Answer 1

Answer:

468

Step-by-step explanation:

0,6,12,18 are in ap

sum of 13 terms is

n/2 (2a+(n-1)d)

therefore s13 is equal to 13/2 (0+(12)6)

13/2 (72)

13×36

468.

please mark this answer brainliest