Find the sum of the first 15 multiples of 8is the sum of first 100multiples of 8
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0
Answer:
Sum of first 15 multiples of 8 is
8+16+24+32+40+48+56+64+72+80+88+96+104+112+120=960
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2
Answer:
a = 8
n = 15
d = 8
So,Sn = n/2 [2a +(n-1)d)
= 15/2 (2×8 + (14)8]
= 15/2 [16 +112]
= 15/2 [128]
= 15 [64]
= 960
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