Find the sum of the first 15 terms of an ap whose nth term is 3-2n
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Given: nth term is 3-2n
To find: the sum of the first 15 terms of an ap
Solution:
- Now we have given the nth term of AP as: 3 - 2n
- Lets put n = 1, we get :
a1 = 3 - 2 = 1
- Lets put n = 2, we get
a2 = 3 - 4 = - 1
- Now from these two terms, we get common difference as:
d = -1 - 1
d = -2
- Lets put n = 15, we get
a15 = 3 - 30
a15 = -27
- So the sum of 15 terms will be: n/2(a+l)
Sum = (15/2)[1 + (-27)]
Sum = (15/2) × - 26
Sum = -195
Answer:
So the sum of 15 terms is -195
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