find the sum of the first 15 terms of an AP whose nth term is 9-5n
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Let n=1
9-5×1=4
Now,n=15
9-5×15= -66
Sn = n/2(a+l)
=15/2(4-66)
= 15×-31
=-465
9-5×1=4
Now,n=15
9-5×15= -66
Sn = n/2(a+l)
=15/2(4-66)
= 15×-31
=-465
Answered by
4
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