Find the sum of the first 16 terms of the AP 10,6,2,.......
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here a= 10
d = 6 - 10 = -4
n = 16
we know that
Sn = n/2(2a+(n-1)d
S16 = 16/2 (20+ (15 * -4)
= 8 (20 + ( -60)
= 8 (-40)
= -320
thanks
mark as brainlist
d = 6 - 10 = -4
n = 16
we know that
Sn = n/2(2a+(n-1)d
S16 = 16/2 (20+ (15 * -4)
= 8 (20 + ( -60)
= 8 (-40)
= -320
thanks
mark as brainlist
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