find the sum of the first 18 term of the arithmetic progression 12b,8b,4b
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Answer:
12b,8b,4b.
s18=?.
First term=a=12b.
Common difference=d=a2-a1=8b-12b=-4b. (Because +×-=- & largest number is important).
sn=2a+(n-1)d.
s18=2(12b)+(18-1)(-4b).
s18=24b+(17)(-4b).
s18=24b-68b.
s18=-44b.
I think this is your answer.
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