Math, asked by sudeesudee64gmailcom, 8 months ago

Find the sum of the first 18 terms, of the
arithmetic progression 12b, 8b, 4b, ......
(A) 126b
(B) -56b
(C) 256b
(D) - 288b
Answer if known​​

Answers

Answered by manjunathamanju72691
0

Answer:

-56b is the answer for question.but you have try again this problem this problem is very is.its so funny

Answered by sakshisharma7406
0

Answer:

comman difference(d)=8b-12b

=-4b

first term(a)=12b

nth term =a+(n-1)×d

18th term =12b+(18-1)×-4b

=12b+17×-4b

=12b-68b

= -56b

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