Find the sum of the first 18 terms, of the
arithmetic progression 12b, 8b, 4b, ......
(A) 126b
(B) -56b
(C) 256b
(D) - 288b
Answer if known
Answers
Answered by
0
Answer:
-56b is the answer for question.but you have try again this problem this problem is very is.its so funny
Answered by
0
Answer:
comman difference(d)=8b-12b
=-4b
first term(a)=12b
nth term =a+(n-1)×d
18th term =12b+(18-1)×-4b
=12b+17×-4b
=12b-68b
= -56b
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