Question

find the sum of the first 20 terms of the A.p 3,3,3,3​

Answer 1

Answer:

a=3

d=0

$sum = \frac{n}{2} (2a + (n - 1)d) \\ sum = \frac{20}{2} (2 \times 3 + (20 - 1)0) \\ = 10(6 + (19)0) \\ = 10(6 + 0) \\ 60 \: is \: the \: answer$

Answer 2

Answer:

Step-by-step explanation:

AP:3,3,3,3,....

a=3

d=3-3=0

n=20

Sn=n/2[2a+(n-1)d]

S20=20/2[2(3)+(20-1)(0)]

= 10[6+0]

= 60