find the sum of the first 200 natural numbers
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Answer:
A = 1
d = 1
n = 200
Sn = n/2[ 2a +(n-1) d]
Required sum = 200/2 [ 2 × 1 + (200 - 1)(1)]
= 100 ( 2 + 199)
= 100 × 201
= 20100
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