Math, asked by saisksaisk2, 1 month ago

find the sum of the first 200 natural numbers​

Answers

Answered by ROYALNINJA
0

Answer:

A = 1

d = 1

n = 200

Sn = n/2[ 2a +(n-1) d]

Required sum = 200/2 [ 2 × 1 + (200 - 1)(1)]

= 100 ( 2 + 199)

= 100 × 201

= 20100

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Answered by diti10sussa
1

Step-by-step explanation:

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