Find the sum of the first 21 terms of the AP: 21, 28, 35, 42, 49, 56,......
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hi.........
here's the answer
a = 21 : d = 28-21 = 7 ; n = 21
S = n/2 ( 2 a + ( n - 1 ) d )
S = 21/2 ( 2 (21) + (21 - 1 ) 7 )
S = 21/2 ( 42 + (20) 7 )
S = 21/2 (42+140)
S = 21/2 (182)
S = 21(91)
S = 1911
#hope this helped u
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