Question

find the sum of the first 22 terms of an A.P., whose common defference is 7 and the 22nd term is 149​

Answer 1

Step-by-step explanation:

I hope it is helpful to you :)

Answer 2

Answer:

1635

Step-by-step explanation:

Step-by-step explanation:

To find = S22

Given : d=7 ; n th term = 22

Solution :

a n = a+[n-1]d

149 = a +[22-2]7

149=a+140

149-140=a

9=a

:. Sn = n/2[2a+(n-1)d]= 22/2[2 x 9 + (22-1) 7]= 11[18+147]= 1635

THEREFORE THE ANSWER IS 1635 .