Question

find the sum of the first 22 terms of an AP 2, 7, 12...​

Answer 1

Answer:

Here the values for d=7 and t

22

=149. Mathematically, this can be written as t

n

=a+(n−1)d

i.e. 149=a+21×7

Or a=149−147=2

Thus, using now the formula for the sum of n terms of the arithmetic progression, we have S

n

=

2

n

[2a+(n−1)d].

Or, substituting the values we have S

22

=

2

22

[2×2+21×7]=11[4+147]

Thus, S

22

=1661.

Answer 2

Answer:

The answer for your question is 1134

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