Question

Find the sum of the first 22 terms of the :-

A.P = 8, 3, -2, ....
​

Answer 1

a=8,

d=3-8=-5

n=22

s=n/2[2a+(n-1)]

s= 22/2(16+21-5)

s=11(16-105)

s=11(-89)

s=-979

Answer 2

Answer:

★ Question :-

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⟶ Find the sum of the first 22 terms of the :-

• A.P = 8, 3, -2, ....

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★ Answer :-

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• $\bold\pink{A.P = 8, 3, -2, .... -979}$

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★ Explanation :-

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⠀⟶ Given :- ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

• A = 8
• D = -5
• N = 22

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⠀⠀⠀$\rightarrow \boxed{\ \bold{ \red {Formula \: Required :- }}} \\ \\ \bold {S = \frac{n}{2}[2 \: a + (n - 1) \times ( d)] } \\ \\ \\ \ \maltese \: \boxed{ \large\bold\pink{Solution :- }} \\ \\ \bold{ = \cancel\frac{22}{2} [2 \times 8 + (22 - 1) \times ( - 5)] } \\ \\ \bold{ = 11[16 + 21 \times ( - 5)] } \\ \\ \bold{ = 11[16 - 105] } \\ \\ \bold{ = 11 \times ( - 89)} \\ \\ = \underline{\boxed { \bold \red{ - 979}}}$

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★ Hence,

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• The value of 22 term = $\bold\red{-979}$

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