find the sum of the first 23 term of an AP 7, 10.5, 14?
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Answered by
0
Answer:
1046.5
Step-by-step explanation:
Hi,
Given A.P is 7, 10/2, 14,......
We can clearly observe that
First Term of an A.P , a = 7
Common difference of A.P, d = 10 1/2 - 7 = 21/2 - 7 = 7/2
Sum to n terms of an A.Pis given by
S = n/2*[2a + (n-1)d]
To find the sum to 23 terms of an AP,
n = 23
So, S = 23/2[2*7 + (22)7/2]
=> S = 23/2[ 14 + 77]
=> S = 23/2*91
=> S = 2093/2 = 1046.5
Hope, it helped
1046.5
Step-by-step explanation:
Hi,
Given A.P is 7, 10/2, 14,......
We can clearly observe that
First Term of an A.P , a = 7
Common difference of A.P, d = 10 1/2 - 7 = 21/2 - 7 = 7/2
Sum to n terms of an A.Pis given by
S = n/2*[2a + (n-1)d]
To find the sum to 23 terms of an AP,
n = 23
So, S = 23/2[2*7 + (22)7/2]
=> S = 23/2[ 14 + 77]
=> S = 23/2*91
=> S = 2093/2 = 1046.5
Hope, it helped
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