Question

find the sum of the first 24 terms of the A.P 8,16,24,32
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Answer 1

$\mathfrak \red{here \: is \: you r \: answer : } \\ a = 8 \\ d = 8 \\ n = 24 \\ s_{24} = \\ s_{24} = \frac{n }{2} (2 \times 8 + (24 - 1)(8)) \\ s_{24} = \frac{24}{2} (16 + (23)8)) \\ s_{24} = 12(16 + 184) \\ s_{24} = 12(200) \\ { \boxed{ s_{24} = 2400}}$

Hope my answer will help you..

Answer 2

Sum Of First 24 Terms = 2,400

Given:

AP = 8,16,24,32

First term of the Arithmetic Progression (a) = 8

Calculating the Common difference of the Arithmetic Progression (d):

= a2 - a1

Putting values we get:

= 16 - 8

= 8

Therefore, the common difference of the AP is 8.

To Find:

The sum of first 24 terms of the AP.

Calculating:

Formula we use to find the sum of n terms of an AP:

Sn = n/2(2a + (n - 1) d)

Substituting all the values known to us in this formula we get:

Sn = 24/2(2 x 8 + (24 - 1) x 8)

Sn = 12 x (16 + (23) x 8)

Sn = 12 x (16 + 184)

Sn = 12 x (200)

Sn = 2,400

Therefore, the sum of first 24 terms of the AP is 2,400.