Question

Find the sum of the first 24 terms of the list of numbers whose n th term is given by an=3+2n

Answer 1

an=3+2n

let take n as 1
a1=3+2(1)
a1=5

now, n as 2
so a2=3+2(2)
a2=7

d=a2-a1=7-5=2

sum:

Sn=n/2(2a+(n-1)d)

s24=24/2(2×5+(24-1)2)

=12(10+(23)2)

=12(10+46)

=12×56

=672

I hope this will help u

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Answer 2

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