Find the sum of the first 25 terms of the arithmetic sequence2, 6, 10, 14 ………..
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Answered by
0
Answer:
clearly common difference is 4
a= 2
so sum ka formula lagao
You will get 1225
Answered by
4
Answer:
The sum of the first 25 terms of the given AP is 1250.
Step-by-step-explanation:
The given arithmetic progression is 2, 6, 10, 14, ....
- a = t₁ = 2
- d = t₂ - t₁ = 6 - 2 = 4
We have to find the sum of the first 25 terms of the AP.
We know that,
Sₙ = ( n / 2 ) * [ 2a + ( n - 1 ) * d ]
⇒ S₂₅ = ( 25 / 2 ) * [ 2 * 2 + ( 25 - 1 ) * 4 ]
⇒ S₂₅ = ( 25 / 2 ) * ( 4 + 24 * 4 )
⇒ S₂₅ = ( 25 / 2 ) * 4 ( 1 + 24 )
⇒ S₂₅ = 25 * 4 ÷ 2 * 25
⇒ S₂₅ = 25 * 2 * 25
⇒ S₂₅ = 50 * 25
⇒ S₂₅ = 1250
∴ The sum of the first 25 terms of the given AP is 1250.
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